Article
Keywords:
Sylow number; non-solvable group
Summary:
We prove that if the average number of Sylow subgroups of a finite group is less than $\tfrac {41}{5}$ and not equal to $\tfrac {29}{4}$, then $G$ is solvable or $G/F(G)\cong A_{5}$. In particular, if the average number of Sylow subgroups of a finite group is $\tfrac {29}{4}$, then $G/N\cong A_{5}$, where $N$ is the largest normal solvable subgroup of $G$. This generalizes an earlier result by Moretó et al.
References:
[2] Conway, J. H., Curtis, R. T., Norton, S. P., Wilson, R. A.:
Atlas of Finite Groups. Maximal Subgroups and Ordinary Characters for Simple Groups. Clarendon, Oxford (1985).
MR 827219 |
Zbl 0568.20001